the angle of elevation of a cloud from a point 60 m above a lake is 30° and the angle of depression of the reflection of the cloud in the lake is 60 degree find the height of the cloud
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Let AO = H
CD = OB = 60 m
A' B = AB = 60 + H
In ∆ AOD,

Now, In ∆ A'OD,

⇒ 120 + H = 3H
⇒ 2H = 120
⇒ H = 60 m
Thus, height of the cloud above the lake = AB + A'B = 60 + 60 = 120 m.
CD = OB = 60 m
A' B = AB = 60 + H
In ∆ AOD,

Now, In ∆ A'OD,

⇒ 120 + H = 3H
⇒ 2H = 120
⇒ H = 60 m
Thus, height of the cloud above the lake = AB + A'B = 60 + 60 = 120 m.
pruthvi30:
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Answer:
Let A be the cloud and D be its shadow.
BC = 60 m
Height of cloud = h m .
Total height of cloud = h + 60 m
In Δ ABE
h / x = tan 30
x = h √ 3
In Δ BDE
h + 60 + 60 / x = tan 60
h + 120 = x √ 3
2 h = 120
h = 60 m .
Therefore , height of cloud from surface of water = ( 60 + 60 ) = 120 m .
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