the angle of elevation of a cloud from a point 60m above a lake is 30 degree and the angle of depression of the reflection of the cloud in the lake is 60 degree find the height of the cloud
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Let AO=H
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
hope it will help you
please mark as it brainlist
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
hope it will help you
please mark as it brainlist
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Answered by
2
this is the answer height will be h+60=90
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Shakthi04:
Your diagram is wrong
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