The angle of elevation of a cloud from a point10 m above the surface of lake is 30 degree and the angle of depression of the reflection of cloud in the lake is 60 degree find the height of cloud
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Let AO=H
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
This sign ( ' ) represents degree ..
anitasaini197:
Plz give me figure of this question...
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