the angle of elevation of a cloudfrom a point is 60M above the surface of the water is of a lake is 30 degrees and the angle of depression of its shadow from the same point is 60 degree find the height of the cloud from then surface of water
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Let AO=H
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
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