Question

the angle of elevation of a jet fighter from a point a on the ground is 60 degree after a flight of 10 seconds the angle of elevation changes to 30 degree if the jet is flying at a speed of 432 kilometre per hour find the constant height at which the jet is flying​

Answer 1

Answer:

here is ur answer mate

Step-by-step explanation:

we have angle of elevation of jet is 60°

after 10 seconds it is 30°

speed of jet is 432 km pr hour

to find height---

• first we have

tan 60°=P/B

let perpendicular be the height which is h metre

tan60°=h/x. (AB=x)

√3=h/x

x√3=h

now we have. speed=d/t

432 km/hr into m/s

432×5/18 =120m/s

putting formula

120=d/10

d=1200m

d is the distance between flight QR

.now tan30°=P/B

1/√3=h/1200

h=1200=h√3

h=1200/√3=h

u can rationalise it

u will get h=400√3 which is the required height

the figure is attached