Math, asked by 9973024283, 1 year ago

the angle of elevation of a jet fighter from a point a on the ground is 60 degree after a flight of 15 second the angle of elevation changes to 30 degree if the date is flying at a speed of 720 km per hour kilometre per hour find the constant height at which the Jets flying

Answers

Answered by hemant87243gmailcom
0
ans.
H=2598m

I hope it's correct answer

9973024283: but how
9973024283: show process
Answered by sweetandsimple64
0
hey here is your answer

Let A be the point of observation on the ground and B and C be the two positions of the jet. Let BL=CM = h metres. Let AL = x metres.

Speed of the jet = 720 km/hr =720m/sec = 200 m/sec

Time taken to cover the distance BC is 15 sec.

Distance BC = LM = 20015 m = 3000 m

InALB,

cot 60° =

=

x=……………….. (i)

InAMC,

cot 30° =



x+3000 = h

x= h-3000 ………………(ii)

From (i) and (ii)

h-3000 =

3h-3000= h

2h= 5196

h=2598

Thus, the height at which the jet is flying is 2598 m.

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sweetandsimple64: make it brainliestplease
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