The angle of elevation of a jet fighter from a point A on the ground is 60degree.after a fight of 15 seconds ,the angle of elevation changes to 30 degree .If the jet is flying at a speed of 720km/hr,find the constant height at which the jet is flying
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H =2598 m =2.598 km ≈ 2.6 km
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⇰Let O be the point of observation on the ground OX.
⇰Let A and B be the two positions of the jet.
⇰ Equating the value of x from (1) and (2),we get;
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