Question

The angle of elevation of a jet fighter from point A on ground is 60°. After flying 10 seconds the angle changes
to 30. If jet is flying at speed of 648km/hr. find the constant height at which jet is flying.
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Answer 1

Answer:

Step-by-step explanation:

light is just a flying at a speed of 648 km per hour

= 648000/3600  m/s

= 180 m/s

Distance covered in 10 secs = 180 * 10 = 1800  m

Height at which flying = H  m

H/Tan30 - H/Tan60  = 1800

=> H√3  - H/√3  = 1800

=> 3H - H = 1800√3

=> 2H = 1800√3

=> H = 900√3 = 1,558.8 m

the constant height at which the Jets flying = 900√3 = 1,558.8 m