Question

the angle of elevation of a jet fighter point a on the ground is 60 degree after 19 second the angle changes to 30 degree if the jet is flying at a speed of 648 kilometre per hour find the constant height of which the jet fly​

Answer 1

Answer:

1596

Step-by-step explanation:

speed=648km/h , time =19 sec

distance=speed ×time

648×19=3192

tan60=p/b

root 3=p/x

x=root3x

tan 30=p/b

1/root3 =x/3192+x

3192+x=root3x

3192+x=root3×root3x

3192+x=3x

3192=3x-x

3192/2=x=1596