Question

The angle of elevation of a jet plane a point A ground is 45 after a flight of 10 seconds. The angle of elevation change to 60 if the jet plane flying at a constant height 3km draw a suitable diagram to find the speed of plane​

Answer 1

speed of plane​ = 456.5 km/hr

Step-by-step explanation:

Tan 45  = Vertical height of plane / horizontal Distance of Plane from point A

=> 1 = 3 / horizontal Distance of Plane from point A

=> horizontal Distance of Plane from point A = 3 km

Let say plane fly for d km

Tan 60   =  3/(3 - d)

=> √3 = 3/(3 - d)

=> 3 - d = √3

=> d = 3 - √3

=> d = 3 - 1.732

=> d = 1.268 km

Time = 10 sec  = 10/3600 hr

speed = 1.268 * 3600/10  = 456.5 km/hr

speed of plane​ = 456.5 km/hr

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