the angle of elevation of a jet plane from a point a on the ground is 45 degree after a flight of 15 seconds the angle of elevation changes to 30. if the jet plane is flying at a constant height of 2500 m find the speed of the jet plane in km/hr.
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The speed of jet plane is 439.2304 km/hr
- First draw the figure for the given question.
- Now find the distance on the ground at 45° using tan(A)=opposite side/adjacent side. You will get distance equal to 2500m.
- Similarly, find distance for angle at 30°, then subtract the distance for 45° from 30° you will get distance =1830.1270m.
- Now using formula speed=distance/time you will get speed=122.0084m/s.
- To get it in km/hr multiply it by 18 and divide by 5 or multiply by 3600 and divide by 1000
- So your answer is 439.2304 km/hr.
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