the angle of elevation of a jet plane from a point a on the ground is 60 degree after a flight of 10 seconds the angle of elevation changes to 30 degree if the flight is just a flying at a speed of 648 km per hour find the constant height at which the Jets flying
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the constant height at which the Jets flying = 900√3 = 1,558.8 m
Step-by-step explanation:
flight is just a flying at a speed of 648 km per hour
= 648000/3600 m/s
= 180 m/s
Distance covered in 10 secs = 180 * 10 = 1800 m
Height at which flying = H m
H/Tan30 - H/Tan60 = 1800
=> H√3 - H/√3 = 1800
=> 3H - H = 1800√3
=> 2H = 1800√3
=> H = 900√3 = 1,558.8 m
the constant height at which the Jets flying = 900√3 = 1,558.8 m
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