the angle of elevation of a jet plane from a point. A. on the the ground is 60^.After the flight of 15 seconds the angel of elevation changes to 30^.If the jet plane is flying at a constant height of 1500√3m, find the speed of the jet plane
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Answer:
Let D and E be the initial and final positions of the plane respectively
Consider the △ABD
tan60
∘
=
AB
BD
⇒
3
=
AB
1500
3
⇒AB=1500
Consider the △ACE
tan30
∘
=
AC
CE
⇒
3
1
=
AC
1500
3
⇒AC=4500
BC=AC−AB=4500−1500=3000m
DE=BC=3000m
i.e., the plane travels a distance of 3000 m in 15 seconds.
∴, speed of the plane =
15
3000
=200m\s
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