Question

The angle of elevation of a jet plane from
a point p on the ground is 6o. After
a flight o 15 seconds, the angle of elevation
changes to 30. If the jet plane is flying
at a constant height of 1500√3m, the find
the speed of the jet plane.​

Answer 1

Answer:

Step-by-step explanation:

Please see the attached file

In triangle ABC,

tan60=BC/AB=3600*3(1/2)

AB=BC/tan60=3600*3^(1/2)/3^(1/2)

AB=3600

In triangle ADE,

tan30= DE/AD

AD=DE/tan30=3600*3^(1/2)/(1/3^(1/2))

AD=3600*3

AD=10800

The distance traveled by the jet plane=AD-AB=10800-3600=7200

So, the speed of the jet plane=7200/30=240

Therefore, the speed of the jet plane is 240 m/s.

Answer 2

SPEED OF PLANE = 720 KM/HR

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