Math, asked by pranavmofficial2005, 7 months ago

the angle of elevation of a jet plane from a point p on the ground is 60 degrees. after a flight of 15 seconds the angle of elevation changes to 30 degrees.if the jet plane is flying at a constant height of 1500 root 3, find the speed of jet plane in km/h. please solve it with diagram

Answers

Answered by harpreetsingh4866
2

 (Draw diagram based on gives conditions. mark E , D,C  points down and A,B points up.)

Tan 60 = AD/ED

= 1500/ED

ED = 1500

Tan 30 = BC/EC

1/ = 1500√3/EC

DE = EC - ED

4500-1500

= 3000

PLANE TRAVELS 3000 m  in 15 sec.

speed = Dstance/Time

= 3000/15

200 m/s.

Jet plane speed = 200m/s.

:)

:)

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