The angle of elevation of a jet plane from a point P on the ground is 60 degree.After a flight of 15 seconds the angle of elevation changes to 30 degree.If the jet plane is flying at a constant height of 1500?3 m ,find the speed of the jet plane.[200m/s Ans.]
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(Draw diagram based on gives conditions. mark E , D,C points down and A,B points up.)
Tan 60 = AD/ED
= 1500/ED
ED = 1500
Tan 30 = BC/EC
1/ = 1500√3/EC
DE = EC - ED
4500-1500
= 3000
PLANE TRAVELS 3000 m in 15 sec.
speed = Dstance/Time
= 3000/15
200 m/s.
Jet plane speed = 200m/s.
Hope This Helps :)
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