Question

The angle of elevation of a jet plane from point a on the ground is 60 degree after a flight of 30 seconds the angle of elevation changes to 30 degrees at the jet plane is flying at a constant height of 3000 root 3 find the speed of a jet plane

Answer 1

Answer:

Step-by-step explanation:

Tan 60 = AD/ED

= 1500/ED

ED = 1500

Tan 30 = BC/EC

1/ = 1500√3/EC

DE = EC - ED

4500-1500

= 3000

PLANE TRAVELS 3000 m  in 15 sec.

speed = Dstance/Time

= 3000/15

200 m/s.

Jet plane speed = 200m/s.

Answer 2

Answer:

Step-by-step explanation:in the question the height of the jet is given as 3000√3

First take tan60

It will give the distance between the point and the initial position of the jet say x and let the distance it covered in the journey be y

tan60=3000√3/x

√3=3000√3/x

x=3000metres

tan30=3000√3/(x+y)

1/√3=3000√3/(3000+y)

3000+y=3000√3*√3

3000+y=9000

y=6000

Speed=distance/time

Speed=6000/30

Speed=200m/s