Question

the angle of elevation of a jet plane from point a on the on the ground is 60 degree after a flight of 30 seconds the angle of elevation changes to third degree if the jet plane is flying at a constant height of 3600 root 3 metres find the speed of jet plane​

Answer 1

Answer:

240 m/s

Step-by-step explanation:

In triangle ABC,

tan60=BC/AB=3600*3(1/2)

AB=BC/tan60=3600*3^(1/2)/3^(1/2)

AB=3600

In triangle ADE,

tan30= DE/AD

AD=DE/tan30=3600*3^(1/2)/(1/3^(1/2))

AD=3600*3

AD=10800

The distance traveled by the jet plane=AD-AB=10800-3600=7200

So, the speed of the jet plane=7200/30=240

Therefore, the speed of the jet plane is 240 m/s.

Answer 2

Answer:

240m/s.

Step-by-step explanation:

In triangle ABC,

tan60=BC/AB = 3600*3(1/2)

AB =BC/ tan60 = 3600 * 3^(1/2)/3^(1/2)

AB = 3600

IN triangle ADE,

tan30 = DE/ AD

AD= DE/ tan30 = 3600*3^(1/2)/(1/3^(1/2)

AD = 3600* 3

AD= 10800

The distance travelled by the jet plane = AD- AB = 10800- 3600= 7200

SO, The speed of the jet plane = 7200/ 30 = 240

therefore, the speed of the jet plane = 240m/s