Question

the angle of elevation of a plane from a point on the ground is 45 degree...after 15 seconds of flight the angle of elevation changes to 30 degree ...if the aeroplane is flying at a constant height of 3000 m find the speed of the plane please give the answer in m/s..... thanks in advance....

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

From right angled △ABC,

tan 30˚ = AC/BC

⇒ 1/√3 = 90m/BC

⇒ BC = [90 × √3] m

∴ BC = 155.88 m

Again from right angled △ACD,

tan 45˚ = AC/CD

⇒ 1 = 90 m/CD

⇒ CD = 90 m

Hence, the distance between the two ships = BC + CD = (155.88 + 90) m

= 245.88 m