The angle of elevation of a tower at a point 90 m from it is cot-1(4/5).Then the height of the tower is.
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Answer:
The height of the tower is 72m.
Step-by-step explanation:
cot-¹ (4/5) = tan 4/5
tan a = AB / BC
4/5 = x / 90
4 = x / 18
x = 72m
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