Question

The angle of elevation of a tower from a point 100 meters from it is 30° find the height of the tower?

Answer 1

tan 30 =h/100
1/root3 =h/100
h=100×root3=100×1.732=173.2m

Answer 2

when theta is 30
tan 30=1/√3
here b=100 meters
tan 30= p/b=1/√3
p/100=1/√3
p=100/√3