| The angle of elevation of a tower from a point on the level ground is 30°. After walking 80m towards the foot of the tower, the angle of elevation of the tower becomes 45°. Find the height of the tower correct up to one decimal place.
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Answer
In ΔADC
tan30
o
=
AC
DC
h
→d=
3
×10
3
=30m
In ΔBCD
tan60
o
=
BC
DC
3
=
d−20
h
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