Question

The angle of elevation of a tower from point p due north of it is 30 degree and from a point q due to east of point p is theta if the distance of foot of tower from point p is 3m and pq is root 3 then theta is equal to

Answer 1

Thank you for asking this question. Here is your answer:

We will let ∠CAD = θ

∠CBD = 90° - θ

In ΔCDA,  CD/AD = tan θ

CD /a m = tan θ --- (1)

In ΔCDB, CD/BD = tan (90° - θ)

CD / bm = cot θ

CD/ bm = 1/ tan θ

CD / bm = am/ CD

CD² = ab m²

CD = √ab m

So the height of the tower is √ab m

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