Question

the angle of elevation of a tower from two points a and b(a>b) from its foot and in the same straight line from it are 30º and 60º,then the height of the tower is

Answer 1

Answer:

the angle of elevation of a tower from two points a and b(a>b) from its foot and in the same straight line from it are 30º and 60º,then the height of the tower is

Step-by-step explanation:

90°

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Answer 2

Answer:

Let PQ be the tower and Q be the top of the tower.Let A and B be the two points at a distant a and b from it's foot. The angle of elevation of the tower from A is 60 degree and from B is 30 degree.

In triangle APQ, (PQ/PA)=tan 60

ie. PQ/a = √3. This Implies PQ=√3.a units.

OR

In triangle BPQ, (PQ/PB) =tan 30.

ie. PQ/b =1/√3. This implies PQ = b/√3 units

So height of the tower is either √3.a units or

b/√3 units.

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