Question

The angle of elevation of a tower is observed to be 45 degree at the end of a horizontal baseof 120 m measured from its feet. Find the height of tower.

Answer 1

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Answer 2

Figure:-

Given:-

• The angle of elevation of a tower is observed to be 45°
• The distance from B to C = 120 m

To find:-

• Find the height of the tower ?

Solutions:-

• Let the height of the tower be 'h' m

According to question:-

We know that,

=> tan∅ = perpendicular/base

=> tan∅ = AB/BC

We have,

The angle of elevation of a tower is observed to be 45°

=> tan 45° = AB/BC

We know that,

The value of tan 45° is 1

=> 1 = h/120

=> h = 120 × 1

=> h = 120m

Hence, the height of the tower is 120m.