The angle of elevation of a tower is observed to be 45 degree at the end of a horizontal baseof 120 m measured from its feet. Find the height of tower.
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Given:
The angle of elevation of a tower is observed to be 45°
The distance from B to C = 120 m
Find:
Height of the tower
Solutions:
Let the height of the tower be 'h' m
We know that,
=> tan∅ = perpendicular/base
=> tan∅ = AB/BC
We have,
The angle of elevation of a tower is observed to be 45°
=> tan 45° = AB/BC
We know that,
The value of tan 45° is 1
=> 1 = h/120
=> h = 120 × 1
=> h = 120m
Hence, the height of the tower is 120m.
I hope it will help you.
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Answered by
1
Answer:
We know that,
=> tan∅ = perpendicular/base
=> tan∅ = AB/BC
We have,
The angle of elevation of a tower is observed to be 45°
=> tan 45° = AB/BC
We know that,
The value of tan 45° is 1
=> 1 = h/120
=> h = 120 × 1
=> h = 120m
Step-by-step explanation:
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