the angle of elevation of a tree at a place 90 meter away is 15° degree . what is height of tree
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Answered by
1
taking tan15 = height / base
hence...
0.85 = height / 90
height = 90 × 0.85
height = 76.5 m....
hence...
0.85 = height / 90
height = 90 × 0.85
height = 76.5 m....
Answered by
1
angle of elevation is 15°
horizontal distance is 90m
tan 15° = (opp)÷(adj)
0.855=((opp)÷(90)
thus, (opp) = 77.039m
it is the required height of tree
horizontal distance is 90m
tan 15° = (opp)÷(adj)
0.855=((opp)÷(90)
thus, (opp) = 77.039m
it is the required height of tree
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