Question

The angle of elevation of an aeroplane from a point A on the ground is 60° After a flight of 30 seconds, the angle of elevation
changes to 300. If the aeroplane is flying at a constant height of 3600V3 metres then find the speed of the aeroplane.​

Answer 1

Answer:

speed = 240m/s.

Step-by-step explanation:

SEE THE PIC ..

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Answer 2

In triangle ABC,

tan60=BC/AB=3600*3(1/2)

AB=BC/tan60=3600*3^(1/2)/3^(1/2)

AB=3600

In triangle ADE,

tan30= DE/AD

AD=DE/tan30=3600*3^(1/2)/(1/3^(1/2))

AD=3600*3

AD=10800

=>The distance travelled by the jet plane=AD-AB=10800-3600=7200

So, the speed of the jet plane=7200/30=240

Therefore, the speed of the jet plane is 240 m/s.

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