Math, asked by mnsumasivakumar, 1 year ago

the angle of elevation of an aeroplane from a point on the ground is 60 degree after a flight of 30 seconds the angle of elevation changes to 30 degree the plane is flying at a constant height of 3600 √3 metre find the speed of the plane in kilometre per hour

Answers

Answered by Aristotle3081
4

Answer:

3600 \sqrt{3} m \: per \: sec =  \frac{3600 \sqrt{3}  \times 18}{5} \\ 750 \times 18 \times  \sqrt{3}  km \: per \: hr

Step-by-step explanation:

remember 1metre per sec is equal to 18 by5 km per hr

Answered by Anonymous
4

In triangle ACE,

CE = 10800 m

AC = BD =

In triangle BED,

CD + DE = CE

CD + 3600 = 10800

CD = 10800 - 3600 = 7200 m

Distance travelled = 7200 m

Time taken = 30 seconds

In 1 second = 240 m

In 3600 seconds (1 hour) = 240 × 3600 = 864000 m = 864 km

In hour = 864 km

Speed = 864 km/h

Pls mark me the brainliest

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