Math, asked by kunshbhatia, 6 months ago

The angle of elevation of an airplane from a point on the ground is 60° . After a flight of 20 seconds, the angle of elevation become 45° from the same point . The airplane is flying at a constant height of 3000√3 ​ m, find the speed of the airplane in km/h? ​

Answers

Answered by Pratyakshajanga
0

Answer:

tan60 degree=3000√3

x=3000√3/1√3=9000m

distance covered = 9000- 3000

= 6000 m.

speed =   30 /6000

​ =200m/s

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kunshbhatia: ???
kunshbhatia: please elaborate
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