The angle of elevation of an airplane from a point on the ground is 60° . After a flight of 20 seconds, the angle of elevation become 45° from the same point . The airplane is flying at a constant height of 3000√3 m, find the speed of the airplane in km/h?
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Answer:
tan60 degree=3000√3
x=3000√3/1√3=9000m
distance covered = 9000- 3000
= 6000 m.
speed = 30 /6000
=200m/s
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