THE ANGLE OF ELEVATION OF THE INACCESSIBLE PEAK OF A HILLOCK FROM ITS FOOT IS 45 DEGREE . AFTER APPROACHING 100m ALONG A SLOPE OF THE HILLOCK , THE ANGLE OF ELEVATION OF THE PEAK AS OBSERVED IS 60 DEGREE. FIND THE HEIGHT OF THE HILLOCK ..??( PLES HELP WITH DIAGRAM )
Answers
Answered by
0
just consider the hillock to be a straight verical line. let its height be h and the distance of the observer from the foot of the line be x. therefore angle of elevation from this point is 45 degrees. hence tan(45) = h/x => h/x = 1 => h=x.
Now when we move closer to the foot by 100 m the angle of elevation increases to 60 degrees. therefore
tan(60) = h/x-100
=> √3 = h/h-100
=> h*(√3 - 1) = 100√3
=> h = 50*(3+√3) = 50*4.732 = 236.6 m
Now when we move closer to the foot by 100 m the angle of elevation increases to 60 degrees. therefore
tan(60) = h/x-100
=> √3 = h/h-100
=> h*(√3 - 1) = 100√3
=> h = 50*(3+√3) = 50*4.732 = 236.6 m
debanti:
ANSWER GIVEN IS 136.6 m
i'm sorry ... there is a slight mistake in my solution .... would u pls write the question again so that i can give the answer...... i'm sorry!!!
Similar questions