the angle of elevation of the top and bottom of a building 50 M high as observed from the top of Tower are 30° and 60° respectively find the height of Tower and also the horizontal distance between the building and the tower
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In the solution of given problem, the knowledge of sin, cos and tan is used. There is the need of correct knowledge and application of these identities. The solution of the problem is attached below. Check it. If you have any confusion, drop the comment in the comment box
According to the figure given in drawn figure,
In Triangle PBC,
tan 60 = BC/PB
√3 = BC /15
BC = 15 x √3
Now in triangle ABC,
tan 30 = AC/ BC
1/√3 = AC / 15 √3
AC = 15
Height of tower = 15 + 15 = 30
Distance between building and tower = BC = 15√3
Step-by-step explanation:
anki337:
you can draw the figure
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