Question

The angle of elevation of the top B of a tower AB from a point X on the ground is 60°
At a point Y, 40m vertically above X, the angle of elevation of the top of the tower is 45°
Find the height of the tower AB and distance XB.​

Answer 1

Step-by-step explanation:

In ΔYCB, we have Height of the tower AB = x + 40 = 20√3 + 20 + 40 = 20√3 + 60 = 20(√3 + 3)Read more on Sarthaks.com - https://www.sarthaks.com/178737/the-angle-of-elevation-of-the-top-b-of-a-tower-ab-from-a-point-x-on-the-ground-is-60-at-a-point

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