Question

the angle of elevation of the top of a building 50 metres high from a point on the ground is 45 degree the distance of the point from foot of the building is
.... Plz help (class 10th)

Answer 1

$\tan(45) = \frac{building \: hight}{distance} \\ = > 1 = \frac{50m}{distance} \\ = > distance = 50m$

Answer 2

Answer:

Let AB be the building of height 50cm

and let CB be the distance from the foot of the building ( Xcm )

perpendicular/base = cot 45°

solve it....