Question

the angle of elevation of the top of a building from a point on the ground which is 30 meters away from the foot of the building is 60°so the height of the building is what​

Answer 1

Answer:

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Answer 2

Answer:

In∆abc we have,

Tan60° =ab/bc

So √3=ab/30

And ab= 30√3

So height of tower =30√3

Step-by-step explanation: