The angle of elevation of the top of a building from a point on the ground, which is 30 m away from the foot of the building, is 30°. The height of the building is
Answers
GIVEN :
• angle of elevation of the top of a building from a point on the ground, which is 30 m away from the foot of the building, is 30°
TO FIND :
• Find the height of tower
SOLUTION :
: Let tower be AB
: Let point C
: Distance of point C from foot of tower = 30m°
: since tower is vertical
:
: We need to find height of tower i.e AB
: In right angle ABC
: Tan C = side opposite angle C / side adjacent angle C
: TAN 30° = AB/ BC
: 1/√3 = AB/ 30
: 30/√3 = AB
: AB = 30/√3
Multiplying √3 is numerator and denominotor
: AB = 30/√3 × √3/√3
: AB = 30√3/ 3
: AB = 10√3
HENCE, THE HIGHT OF TOWER IS AB = 10 √3 m