Question

The angle of elevation of the top of a building from a point on the ground, which is 30 m away from the foot of the building, is 30°. The height of the building is​

Answer 1

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your required answer is in the attachment :)

Answer 2

C be the point which is 30 m away from the tower i.e. BC = 30 m. Let AC be the rope whose length is 20 m, and AB be the vertical pole of height h m and the angle of elevation of A at point C on the ground is 30°. Hence, the height of the pole is 10 m.

In∆abc we have,

Tan60° =ab/bc

So √3=ab/30

And ab= 30√3

So height of tower =30√3