Question

The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the buildings is 60° If the tower is 50 m high, find the height of the building?
No copied answer ❌.

Answer 1

$\huge \fcolorbox{black}{lightblue}{Solution \: is \: Attached \: above.}$

Answer 2

Answer:

16.66 m

Step-by-step explanation:

Given height of tower CD = 50m

Let height of building AB be h

In right angled triangle BDC,

⇒ tan 60 = CD/BD

⇒ $\sqrt{3}$ = 50/BD

⇒ BD = 50/$\sqrt{3}$ m

In right angled triangle ABD,

⇒ tan 30 = AB/BD

⇒ $\frac{1}{\sqrt{3} }$ = $\frac{h}{\frac{50}{\sqrt{3} } }$

⇒ $\frac{1}{\sqrt{3} }$ = $\frac{\sqrt{3} h}{50}$

⇒ h = 50/3 = 16.66m