Math, asked by gunashyamvarada, 23 hours ago

The angle of elevation of the top of a building from the foot of the tower is 30° and the angle of elevation of the top of the tower from the foot of the building is 60°.If the tower is 30m high,find the height of the building.​

Answers

Answered by kaushik4656
0

Answer:

the height of the building is 10 m

Step-by-step explanation:

let the height of the tower=30 m

the height of the building =h m

angle of elevation from the bottom off the building to the top of tower and bottom of the top of building are 60° and 30° .

also ,let AB = xm be the distance between foot of the tower and building.

tan 30°=AD/AB 1/√3= h/x

h=x/√3---(1)

In right angle ∆ BAC , tan 60° =BC/AB

√3=30/x

x =30/√3×√3/√3 = 10√3 m

From (1) we get ,h= x/√3 = 10√3/√3 = 10 m

The height of the building is 10 m

Answered by medhamullapudi1984
0

Answer:

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