The angle of elevation of the top of a building from the foot of the towers 30" and the angle of elevation of the tower from the foot of bulding is 60 if the tower is 30 m high find the height of the building
Answers
Answered by
0
Step-by-step explanation:
Given height of tower CD=50m
Let the height of the building, AB=h
In right angled △BDC,
⇒ tan60
o
=
BD
CD
⇒
3
=
BD
50
⇒ BD=
3
50
m
In right angled △ABD,
⇒ tan30
o
=
BD
AB
⇒
3
1
=
3
50
h
∴
3
1
=
50
3
h
∴ h=
3
50
=16.66m
∴ The height of the building is 16.66m.
Answered by
0
Answer:
10m
Step-by-step explanation:
Given that,
Height of tower = 30m
Let the height of the building = h
In right angled triangle,
=> tan60° = 30/ x
=> √3 = 30/x
=> x = 30/√3 m
Again,
=> tan30° = h/30/√3
=> 1/√3 =√3h/30
=> h = 30/3
=> h = 10 m
The height of the building is 10 m.
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