Question

The angle of elevation of the top of a building from the foot of the tower is 30digree and the angle of elevation of the top of the tower, from the foot of the building is 60digree. If the tower is 50 m high find the height of the building ​

Answer 1

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Answer 2

Hello mate ✨

Let AB be the building and CD be the tower.

In ΔCDB,

CD/BD=tan60°

50/BD=√3

BD=50/√3

In ΔABD,

AB/BD=tan30°

Since, BD=50/√3,

So, AB=50/√3×1/√3

AB=50/3m

Therefore, the height of the building is 50/3 m.