The angle of elevation of the top of a control tower of an airport from a certain distance was 45 degree after moving 120 m from the first point of of observation in line with the foot of the tower the observation was found to be in 30 degree.
Answers
Answered by
3
Answer:
plzzz give me brainliest ans and plzzzz follow me
Attachments:
Answered by
1
Answer:
Step-by-step explanation:
1/√3 = x/BE
BE = x√3m
Tan 60 = AC/CD
√3 = x + 40/CD
CD√3 = x + 40
Since BE is parallel to CD
x√3 x √3 = x + 40
3x = x + 40
3x - x = 40
2x = 40
x = 20
The height of the tower = x + 40
20 + 40 = 60m
The horizontal distance from the point of observation = x√3 = 20√3m
Similar questions