Question

The angle of elevation of the top of a flag pole 5m high from a point on the ground is 60°. Find the distance between point and the foot of the pole

Answer 1

Step-by-step explanation:

Let the height of the tower be h

so $\angle{BAD}=90-45=45∠BAD=90−45=45 °$

the distance of the point A from the foot of tower be b

so so tan 45 =$\frac{h}{b}$

⇒ b = x [ {tan 45° = 1}

for ΔABC $\angle{BAC}=60$

so tan 60° =$\frac{x+5}{x}$

x

x+5

⇒ √3x = x + 5

⇒ 0.732x = 5

⇒ x ≈ 6.83 m ANSWER

Answer 2

Answer:

5√3/3

Step-by-step explanation:

h=5m, Θ=60, distance between point and the foot of the pole= x

tanΘ=h/x

tan60=5/x

√3=5/x

x=5/√3

x=5√3/3