the angle of elevation of the top of a hill at the foot of a tower is 60 degree and the angle of elevation of the top of the tower from the foot of the hill is 30 degree if the tower is 50 M high find the height of the hill
Attachments:
Answers
Answered by
3
I hope this image will help uu
Attachments:
vaishalibaghel45:
thanks u so much
Answered by
1
Answer:
Step-by-step explanation:
Height of tower = 50m
Distance between tower (AB, with A on the ground) and hill (PQ, with P on the ground) (AP) = x m
=> Angle of elevation of hill from A = 60°
Angle of elevation of tower from P = 30°
Height of the hill = h m
In ∆ABP, tan30 = AB/AP = 1/√3
=>50/x = 1/√3
x= 50√3 m
In ∆ PQA, tan60 = PQ/AP = √3
=> h/(50√3) = √3
=> h = 50√3 × √3 = 50 × 3
Therefore, height of the hill (h) = 150m
Similar questions