Math, asked by DebanjanChakrabarty, 11 months ago

the angle of elevation of the top of a hill at the foot of a tower is 60 degree and the angle of elevation of the top of the tower from the foot of the hill is 30 degree if the tower is 50 M high find the height of the hill

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Answered by niranjana4
3
I hope this image will help uu
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vaishalibaghel45: thanks u so much
niranjana4: well come
Answered by sreeharshitha02
1

Answer:


Step-by-step explanation:

Height of tower = 50m

Distance between tower (AB, with A on the ground) and hill (PQ, with P on the ground) (AP) = x m

=> Angle of elevation of hill from A = 60°

Angle of elevation of tower from P = 30°

Height of the hill = h m

In ∆ABP, tan30 = AB/AP = 1/√3

=>50/x = 1/√3

x= 50√3 m

In ∆ PQA, tan60 = PQ/AP = √3

=> h/(50√3) = √3

=> h = 50√3 × √3 = 50 × 3

Therefore, height of the hill (h) = 150m


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