Question

The angle of elevation of the top of a hill from foot of a tower is 60 and the angle of elevation of the top of the tower from the foot the hill is 30. If tower is 50m high, then fi

Answer 1

Given,
Hill(AB)=50m
Tower(CD)=k
angle ADB=60
angle CBD=30


Proof÷let DB be the base of tower and the hill
In triangle ADB
tan60=P/B
√3=AB/DB
√3=50/DB
DB=50/√3

Now in triangle CBD,
tan30=P/B
1/√3=CD/DB
1/√3=k/50/√3
1/√3=k√3/50
50/√3=k√3
50/√3×√3=k
50/3=k

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Answer 2

The angle of elevation of the top of a hill from foot of a tower is 60 and the angle of elevation of the top of the tower from the foot the hill is 30. If tower is 50m high, then fi
Given,
Hill(AB)=50m
Tower(CD)=k
angle ADB=60
angle CBD=30

Proof÷let DB be the base of tower and the hill
In triangle ADB
tan60=P/B
√3=AB/DB
√3=50/DB
DB=50/√3

Now in triangle CBD,
tan30=P/B
1/√3=CD/DB
1/√3=k/50/√3
1/√3=k√3/50
50/√3=k√3