The angle of elevation of the top of a to a tower 30m high from the foot of another tower in the same plane is 60°, and the angle of elevation of the top of the second tower from the foot of the first tower is 30°. Find the distance between the two towers and also the height of the other tower.
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height of the first tower=30m(height)
angle of elevaton from the foot of another tower=60°
tan60° = height/base
√3= 30/base
base=30/√3 m
Now,
angle of elevation from the foot of 1st tower =30°
tan30° = height of tower/base
1/√3 = height of other tower / 30/√3
height of other tower = 30 ÷ √3×√3
height of other tower=10m
angle of elevaton from the foot of another tower=60°
tan60° = height/base
√3= 30/base
base=30/√3 m
Now,
angle of elevation from the foot of 1st tower =30°
tan30° = height of tower/base
1/√3 = height of other tower / 30/√3
height of other tower = 30 ÷ √3×√3
height of other tower=10m
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