Physics, asked by pranjalkeshari4119, 1 year ago

The angle of elevation of the top of a tower, 12m high, at the point on the ground is 30ged. Find the distance of the point from the top of the tower

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Answered by nilesh121

0

ang. ACB=30 deg.

tanACB=AB/BC

tan30=12/BC

√3=12/BC

BC=4√3

BC=6.92m

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