The angle of elevation of the top of a tower 150 meters away was found out to be 30° . Find the
height of the tower.
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Let the height of the tower be h
angle of elevation = <A = 30°
AB = 150m
tanA = BC / AB
tan30° = h / 150
1/√3 = h/150
h = 150/√3
h = 150√3/ 3
h = 50√3
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