The angle of elevation of the top of a tower 30 m height from the foot of another tower in the same plane is 60° , then the distance between two towers
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Answer:
et h= height of second tower, d=distance between two towers
height of first tower = 30 m
From given data,
d
30
=tan60
∘
=
3
d
h
=tan30
∘
=
3
1
3
h=d,30=d
3
h=10 m, d=10
3
m
Therefore, height of the other tower is 10 m
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