Question

The angle of elevation of the top of a tower 40m high from point on the level of ground on its opposite sides are 45 and 60 degree find the distance between two points

Answer 1

Answer:

in ΔADC

tan45°= AD/DC

1= 40/X

X =40

IN ΔABD

tan60 = AD/BD

√3 =40/Y

Y=40/√3

TOTAL LENGTH =X+Y

40 + 40/√3

=(40√3+40)/√3

40(√3+1)/√3